Exactly.
Nobody knows.
Best SNL skit I’ve seen in a long, long time.Nobody knows.![]()
Let us consider the division of two non-zero integers \(a\) and \(b\), where \(a = -3\) and \(b = 5\). The absolute value of \(a\) is less than the absolute value of \(b\), thus satisfying the given condition \(|a| < |b|\). The steps for computing the quotient \(q = a \div b\) are as follows:The Metric system is simple math. The Imperial system is nonsense
I have never had a headache until now, thanks. Letters are not math.Let us consider the division of two non-zero integers \(a\) and \(b\), where \(a = -3\) and \(b = 5\). The absolute value of \(a\) is less than the absolute value of \(b\), thus satisfying the given condition \(|a| < |b|\). The steps for computing the quotient \(q = a \div b\) are as follows:
Calculate the absolute values of \(a\) and \(b\): \(|a| = |-3| = 3\) and \(|b| = |5| = 5\).
Determine the preliminary quotient, \(q'\), by dividing the absolute values: \(q' = |a| \div |b| = 3 \div 5 = 0.6\).
Ascertain the sign of the quotient, \(q\), using the rule of signs for integer division: \(a \cdot b = (-3) \cdot 5 = -15\). Since \(a \cdot b < 0\), the quotient \(q\) is negative.
Hence, the value of the quotient \(q = a \div b\) is \(-0.6\).
See, simple.
Because of the ethanol they mandated on all grades. 91 used to be ethanol free. It makes my lawnmower and snow blower weephalf-assed 91 octane,
FINALLY !