markmurfie
Well-Known Member
I reread it. It’s not any better. The first half is dead wrong and the second half is so fundamental that I wonder if you know what we’re even discussing or where the sticking point actually is.
0 and 1. What do I win? I had high school physics. I’ve been trying to move the discussion on to college level since the beginning.
You win nothing, you are wrong.
0 lbs in space.
mass of 3/4" x 1.5" x 4", but that mass could be spread out in any dimensions you wanted it to be in, so any three distances is right. Because weight is only relevant in the earths gravity frame of reference.
And no I'm not trying to muddy the waters, you don't want to talk about friction. You want to talk about a single object floating in empty space.
Dimension 0 is a point
Dimension 1 is a line
Dimension 2 is a square
Dimension 3 is a cube
Dimension 4 is a moving cube, this movement can be constant or acceleration. In acceleration it's called Time squared, but it could be any two time values multiplied together as the time spent at a constant speed could be different from the one spent accelerating. So you can not use acceleration for a mass equivalence, removing the time spent accelerating would give you a single point of acceleration, which would be a velocity. You would also not use velocity for a mass equivalence, eliminating the time at a constant speed would just be a single point in space/ time. This is because space/time is not a property of the 3rd dimension. Just like volume is not a property of the 2nd dimension, area is not one of the 1st, and length is not one of a point.
When you use mass in these equations you are reducing it down to the physical dimensions of the single object you are referring to.
A dyno measures your engines acceleration, and if you want to ignore that and incorrectly change that, go ahead keep doing it. Its like using a ruler and just subtracting 1/2", just because thats your way or you read it written in a book by someone with a PHD, it doesn't effect me. I'm just trying to tell you, you don't need to do that and you are coming up with the wrong measurements.
How do I calculate acceleration, I don't, I measure it on a dyno as horsepower. Any mass attached to the engine after that, just increases what the total energy output gets distributed to. Knowing that it is a significant amount of mass's moving amongst other mass's, appropriate gear ratios are applied to increase the leverage it has to overcome those extra frictional forces.
"Oh but, torque based ECU tuning blah blah blah", yeah it's dumb.
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